20,25x^2-45x+8=0

Solution for 20,25x^2-45x+8=0 equation:

20.25x^2-45x+8=0

a = 20.25; b = -45; c = +8;
Δ = b2-4ac
Δ = -452-4·20.25·8
Δ = 1377
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1377}=\sqrt{81*17}=\sqrt{81}*\sqrt{17}=9\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-9\sqrt{17}}{2*20.25}=\frac{45-9\sqrt{17}}{40.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+9\sqrt{17}}{2*20.25}=\frac{45+9\sqrt{17}}{40.5}
$